Class 5 Maths Chapter 1 Question Answer | নতুন গণিত পঞ্চম শ্ৰেণী  পাঠ ১ সমাধান

Class 5 Maths Chapter 1 Question Answer Assamese Medium | নতুন গণিত পঞ্চম শ্ৰেণী  পাঠ ১ সমাধান | সংখ্যা আৰু প্ৰক্ৰিয়া

We have provided the solution of Class 5 Maths Chapter 1 Question Answer for Assamese Medium as well as in English also.

The name of Chapter 1 or Lesson 1 is Numbers and Operations which includes addition, subtraction, multiplication of number. Place value and number in words question are also solved.

We have provide the full solution for Class 5 Maths Chapter 1 Numbers and Operations page wise.

আমি অসমীয়া মাধ্যমৰ বাবে ৫ম শ্ৰেণীৰ গণিত অধ্যায় ১ প্ৰশ্নৰ উত্তৰৰ সমাধানৰ লগতে ইংৰাজীতো আগবঢ়াইছো।

অধ্যায় ১ বা পাঠ ১ ৰ নাম হৈছে সংখ্যা আৰু কাৰ্য্য য’ত সংখ্যাৰ যোগ, বিয়োগ, গুণন অন্তৰ্ভুক্ত কৰা হৈছে। শব্দ প্ৰশ্নত স্থানৰ মান আৰু সংখ্যাও সমাধান কৰা হয়।

আমি ৫ম শ্ৰেণীৰ গণিত অধ্যায় ১ সংখ্যা আৰু কাৰ্য্যকলাপৰ সম্পূৰ্ণ সমাধান পৃষ্ঠা অনুসৰি প্ৰদান কৰিছো।

Class 5 Maths Chapter 1 Question Answer Assamese Medium

এই খণ্ডত আমি পঞ্চম শ্ৰেণীৰ গণিতৰ পাঠ্যপুথিৰ দৰে প্ৰশ্নৰ উত্তৰ পৃষ্ঠা অনুসৰি সমাধান দিম।

In this section we will provide solution to question answer page wise as on Class 5 maths textbook.  

Page 1 Class 5 Maths Chapter 1 Question Answer Assamese Medium

(i)  Distance from Nalbari to Sankardev Kalakshetra is  83 km

(ii) Total distance from Kalakshetra to Planetarium is  15 km

(iii) Total distance from Chandmari to Nalbari via Planetarium is 76 km

(i) নলবাৰীৰ পৰা গুৱাহাটীৰ শংকৰদেৱ কলাক্ষেত্ৰলৈ দূৰত্ব 83  কি মি ।

(ii) কলাক্ষেত্ৰৰ পৰা তাৰকাগৃহলৈ মুঠ দূৰত্ব হ’ল 15 কি মি |

(iii) চানমাৰিৰ পৰা তাৰকাগৃহ হৈ নলবাৰীলৈ মুঠ দূৰত্ব 76 কি মি।

Now discuss the following tour related problems in group and solve them–

(i) Total amount collected from 20 students at the rate of Rs. 200/- per student is

Rs. 200/- × 20 = Rs 4000

এইবাৰ ভ্ৰমণৰ লগত জড়িত তলৰ সমস্যাবোৰ দলত বহি আলোচনা কৰি সমাধান কৰা (i) গাইপতি 200 টকাকৈ সংগ্ৰহ কৰিলে 20 জন ছাত্ৰ-ছাত্ৰীৰ পৰা সংগ্ৰহ কৰা মুঠ ধনৰ পৰিমাণ 

200 টকা x 20 =4000 টিকা।

Page 2 Class 5 Maths Chapter 1 Question Answer

(ii) The tour party paid Rs. 2200/- as their bus fare. What amount of the total

collection will remain as balance with them? 

Rs 1800

(iii) Total amount paid to Regional Science Centre as entry fees for 21 persons

(including the teacher) is Rs. 210. and the balance amount left with them

is Rs. 1590

(iv) The total expenditure incurred against food for 21 persons at the rate of Rs.

65/- each is Rs. 65/-×21 = Rs.1365

(v) The balance amount left with the tour party is Rs.225

(vi) An amount of Rs. 450/- was given to Rantu by his father to buy books from the

Book Fair and accordingly he bought the following books– one copy of Burhi

Aair Sadhu at Rs. 66/-, one copy of “Aesopo’s Fables” at Rs. 45/-, one copy

of Spoken English at Rs. 82/- and five copies of colour books at total amount of

Rs. 125/-. What is the total amount of money did Rantu spend in buying the

books from the Book Fair and what balance amount was left with him?

Solution

Burhi Aair Sadhu – Rs 66/-

Aesopo’s Fables – Rs 45/-

Spoken English –   Rs 82/-

Colour books   –     Rs 125/-

_______________________

Total                –  Rs 318/-

Money Spend by Rantu in Buying Books – Rs 318/

Balance Amount Left with Him – Rs 132/

Let us express the numbers in the above sentences in words–

Page 4 Class 5 Maths Chapter 1 Question Answer Assamese Medium

Break up the following numbers into positional values and demonstrate in abacus system as shown above–

Page 5 Class 5 Maths Chapter 1 Question Answer Assamese Medium

Page 6 Class 5 Maths Chapter 1 Question Answer Assamese Medium

Let us practise –

Now, you think of a 5 digit number yourself and try to write it in expanded form in

your note book. Compare your number with those written by others in the class.

Page 7 Class 5 Maths Chapter 1 Question Answer Assamese Medium

Let us express in short form–

1. 800 + 80 + 9 =  889
2. 2000 + 200 + 20 + 2 = 2222
3. 600 + 0 + 30 + 1 = 6031
4. 10000 + 6000 + 500 + 40 + 3 = 16543
5. 30000 + 0 + 0 + 60 + 7 = 30067

Let us express in numbers–

(a) Nine thousand eight hundred five =  9805

(b) Fifteen thousand seven hundred nine = 15709

(c) Thirty five thousand ninety two = 3592

(d) Sixty nine thousand six hundred = 69600

(e) Ten thousand two =2002

Let us express in words–

(a) 15,907 = Fifteen thousand nine hundred seven

(b) 29,008 = Twenty nine thousand eight

(c) 61,507 = Sixty one thousand five hundred seven

(d) 70,091 = Seventy thousand ninety one

(e) 92,990  =Ninty two thousand nine hundred ninty

Let us arrange in ascending order–

Page 8 Class 5 Maths Chapter 1 Question Answer Assamese Medium

Let us write down the greatest and the least five digit numbers using

the digits given below–

Let us write down the positional values of the underlined digits given below–

a) 1 4 6 5 1 =  4000

b) 3 0 7 2 5 = 0

c) 9 2 7 2 5 =90000

d) 8 2 7 1 1 = 80000

e) 6 1 2 4 1 = 200

f) 8 6 7 0 2 = 2

Page 9

Comparing the two numbers, let us put appropriate symbol in the blank space

(a) 38640 < 48694 (e) 10243 < 11000

(b) 10040 > 10004 (f) 44232 < 42432

(c) 87878 > 87877 (g) 32098 = 32098

(d) 60060 < 60600 (e) 10010 < 11010

Let us think over ‘Who I am’–

(i) I am a 5 digit number.

(ii) I am a number immediately preceding to the largest three digit number.

(iii) The digit in my ten thousand’s position is the difference of digits in my

tenth and unit’s positions.

(iv) The digit in my thousandth position represents the standard of my class.

Now write down ‘Who I am’–

10599

Think and fill in the blank spaces :

(a) Positional value of 9 is 95072 in  90000

(b) The least 4 digit number is and the greatest 4 digit number is 1000 and 9999

(c) The number preceding the least 4 digit number is 999

(d) 4563 + 0 = 4563

(e) 10000 – 1000 = 9000

(f) Adding 1 to the largest 4 digit number results in the least  5 digit number.

Page 10 Class 5 Maths Chapter 1 Question Answer

a.  1200 +10 = 1210 and 800+410 = 1210

b.  100 + 516 + 482 = 999

c. 2555 + 3111+ 4333 = 9999

Page 12 Class 5 Maths Chapter 1 Question Answer Assamese Medium

Problems for Practice :

Page 13

Let us subtract :

Practice

Think and find the values–

(a) 3217 + 9673 = 12890 , 12890 – 9673 = 3217

(b) 7612 + 2892 = 10504 , 10504 – 7612 = 2892

(c) 8292 – 6479 = 1813 , 6479 + 1813 = 8292

(d) 9678 – 3859 = 5819 then 3859 + 5819 = 9678

Try to solve the following problems–

(a) Sum of two numbers is 41283. If one of them is 28239, what will be

the other one? 

Solution: 

41283 – 28239 = 13044

(b) What is the difference between 67192 and 73841?

Solution:

73841 – 67192 = 6649

(c) Find the sum of the number 32721, 40621 and 72901.

Solution:

32721 + 40621 + 72901 = 1,46,243

(d) What is to be added to 28709 to get the sum 78239?

Solution:

28709 + 49530 = 78239

Page 14

Look at the following problems on subtraction and fill up the boxes with

appropriate digits

Let us multiply–

Problems for practice

Page 15

Go through the following problems and solve them–

1. At the time of Magh Bihu, Binod’s father earned Rs. 20,000/- by selling Rohu

fish, Rs. 25,500/- by selling Common Carps and Rs. 2,500/- by selling

Catfishes from his own fishery. What amount of money did he earn totally?

Solution:

 Rohu Fish –   Rs. 20,000/-

Common Carps – Rs. 25,500/-

CatFish-       Rs. 2,500/-

______________________

Total Money –  Rs 48,0000/-

2. Monthly income of Rama’s mother is Rs. 15,000/-. She saves monthly Rs.

5000/- from it and keeps in post office as fixed deposit. What amount of

money does she deposit yearly in the post office and what is her monthly

balance from her income?

Solution:

Money deposited in Post Office Yaerly –  Rs. 5000/- X 12 = Rs.60,000/-

Monthly Balace from her income – Rs 15,000 – Rs  5,000 = Rs 10,000

3. 22,345 spectators entered a stadium with a capacity of 25,000 seats to watch

a football match. How many seats remained vacant in the stadium on that

Day?

Solution:

Vacancy Seats = 25,000 – 22,345  = 2655

4. Ramen took 40 kg. of potatoes  to Guwahati for selling. He sold 30 kg. of them

at Rs. 40/- per kg. How much money did he earn?

5. In a block level sports event, a total number of 400 students from 8 schools

participated. If equal number of students from each school participated in the

event, what was the number of participating students from each school?

Conclusion

We have solved all Class 5 Maths Chapter 1 Assamese Medium Question Answers. Page wise solution is given.